pidgeon92 > RE: Fillapix question... (2/26/2020 6:35:21 PM)

I'll try to explain... I suspect there might be an easier method, but the way I look at these puzzles is that I examine each number on the grid as the center of nine blocks (except on the edges, where corner number only have four potential filled blocks, and edge number have only six). Any of those nine blocks can potentially be filled (black vs. null) with the indicated number. In this case, I looked at the 5 that Dve said is the next move. (I have bordered the 5 and its nine surrounding blocks in blue.) So, any combination of 5 of those nine blocks could theoretically be filled in. However, the number 3 (bordered in red) below the 5 already has one block filled in, on the lower right corner. Thus, in the six blocks that the number 5 and number 3 share, only two of those can be filled in, one must be null. This is because there can only be three filled blocks in the nine squares surrounding the number 3. So, the three blocks above the 5 must be filled (blacked) in. Those three, plus the two in the boxes that the 3 and 5 must share, equal five. [image]local://457315/D9F92137480F480C87A626E39D2DAB44.jpg[/image]



