sfglbkf
Posts: 24
Joined: 8/16/2002
From: United States
Status: offline

In the bottom right corner, you can eliminate some more possible values based on nearby squares. In the vertical 14, the lowest the middle square can be is 7, which means the remaining squares can add up to at most 7, so each individual square can't be more than 6. In the horizontal 14, the 2nd and 4th numbers can't add up to more than 7, and since the 1 is already used in that row neither number can be more than 5. Another technique can be used in the vertical 42. Since 2 of the squares can only be 3 or 4, no other square can have a 3 or 4, so the 2nd square must be 5. I don't know how far this will get you, but it at least gives you a few more things to look for.
